Give it an input and say what you think comes back. It compiles and runs for real, so a wrong guess still shows you the answer — probe as much as you like. Only correct predictions count.
Locked until you have predicted 4 outputs correctly.
| 1 | int solution(const string& s) { |
| 2 | int n = s.size(); |
| 3 | unordered_map<char, int> lastSeen; |
| 4 | int start = 0; |
| 5 | int best = 0; |
| 6 | for (int i = 0; i < n; i++) { |
| 7 | char c = s[i]; |
| 8 | if (lastSeen.count(c) && lastSeen[c] >= start) { |
| 9 | start = lastSeen[c] + 1; |
| 10 | } |
| 11 | lastSeen[c] = i; |
| 12 | int width = i - start + 1; |
| 13 | if (width > best) best = width; |
| 14 | } |
| 15 | return best; |
| 16 | } |
Names have been stripped. The signature is the only clue you get for free. Compiled as C++20 with the standard headers and using namespace std; already in scope.